1/2(x+3)^2-9=27

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Solution for 1/2(x+3)^2-9=27 equation: 



1/2(x+3)^2-9=27

We move all terms to the left:

1/2(x+3)^2-9-(27)=0



Domain of the equation: 2(x+3)^2!=0

x∈R



We add all the numbers together, and all the variables

1/2(x+3)^2-36=0

We multiply all the terms by the denominator


-36*2(x+3)^2+1=0

Wy multiply elements

-72x(x+1=0

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